Question : sliding window protocol

In a proprietary selective-repeat sliding window protocol 3 bits have been allocated for sequence numbering. If the subnet uses fixed 1000 byte frame size, how much buffering is required at the source and destination? What should be the size of the ACK field?

Answer : sliding window protocol

Sounds like a homework problem to me (http://www.experts-exchange.com/Community_Support/General/Q_10154559.html?sfQueryTermInfo=1+homework), so let's use the Socratic method:

- If there are three bits for the sequence numbering, how many possible sequence numbers can each packet possibly express?

- Once you know how many sequence numbers are available, can you tell how many packets can be outstanding at one time?

- Based on the number of outstanding packets and the number of bytes per packet, how much memory is therefore needed to hold all of that data in a buffer?

- Is the ACK field any different than the sequence number field?
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